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In Physics / College | 2025-07-08

An electric device delivers a current of [tex]$15.0 A$[/tex] for 30 seconds. How many electrons flow through it?

Asked by Osbssianaiab

Answer (2)

Factor the quadratic expression x 2 + x − 72 .
Find two numbers a and b such that a × b = − 72 and a + b = 1 .
The numbers are 9 and − 8 , since 9 × − 8 = − 72 and 9 + ( − 8 ) = 1 .
Therefore, x 2 + x − 72 = ( x + 9 ) ( x − 8 ) , and the answer is ( x + 9 ) ( x − 8 ) ​ .

Explanation

Understanding the Problem We are given the quadratic expression x 2 + x − 72 and asked to rewrite it in the form ( x + a ) ( x + b ) . This requires us to factor the quadratic expression.

Finding the Factors To factor the quadratic expression x 2 + x − 72 , we need to find two numbers a and b such that their product is equal to the constant term − 72 and their sum is equal to the coefficient of the linear term, which is 1 .

Identifying the Correct Numbers We are looking for two numbers a and b such that a × b = − 72 and a + b = 1 . By trial and error or by considering factor pairs of − 72 , we can find that the numbers are 9 and − 8 , since 9 × − 8 = − 72 and 9 + ( − 8 ) = 1 .

Writing the Factored Form Therefore, we can write the quadratic expression as ( x + 9 ) ( x − 8 ) . So, a = 9 and b = − 8 (or vice versa).

Final Answer The factored form of the given expression is ( x + 9 ) ( x − 8 ) .


Examples
Factoring quadratic expressions is a fundamental skill in algebra and is used in many real-world applications. For example, engineers use factoring to design structures, ensuring stability and optimal use of materials. Imagine designing a rectangular garden where you know the area and need to find the dimensions. If the area is represented by a quadratic expression, factoring helps determine the possible lengths and widths of the garden. This skill is also crucial in physics for solving equations related to motion and forces.

Answered by GinnyAnswer | 2025-07-08

About 2.81 × 1 0 21 electrons flow through the device when it operates with a current of 15.0 A for 30 seconds. This is calculated by first determining the total charge (450 Coulombs) and then dividing that by the charge of a single electron (1.602 x 10^-19 Coulombs). Hence, the total number of electrons flowing is significant, illustrating the large quantities of charge moving in electrical circuits.
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Answered by Anonymous | 2025-08-01