Select the correct answer.
What is the solution to this equation?
$\log _8 16+2 \log _8 x=2$
A. $x=-2$
B. $x=0$
C. $x=2$
D. $x=4$

First.
Calculate f'(x) = (2x/x-1)' = (-2)/ ( x − 1 ) 2 ; when x is not 1;
Second.
Calculate f'(0) = -2 => the difference quotient (f(a+h)-f(a))/ h, where hod want equal 0 is -2;
Third.
f(a) = 2a/a-1; f(a+h) = (2a+2h)/(a+h-1);

Answered by crisforp | 2024-06-10

1 ;

Answered by titir15 | 2024-06-12

To find f ( a ) , use f ( a ) = a − 1 2 a ​ . For f ( a + h ) , use f ( a + h ) = a + h − 1 2 ( a + h ) ​ . The difference quotient is given by ( a + h − 1 ) ( a − 1 ) 2 ( ah − a + h ) ​ .
;

Answered by crisforp | 2024-12-04