Δ = 19^2 - 4 5 12 => Δ = 121 => d e lt a = 11; x1 = -0.8; x2 = -3; 5x^2+19x+12 = 5( x + 0.8)( x + 3) = ( 5x + 4)( x + 3);
(
x −
3 )( 5x −
4 ) ;
The polynomial 5 x 2 + 19 x + 12 factors to ( 5 x + 4 ) ( x + 3 ) . This was achieved by finding two numbers that multiply to 60 and add to 19, which were 15 and 4. By grouping the terms and factoring, we reached the final result.
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