Find the critical point of the function $f(x, y)=4-8 x-2 x^2+3 y-6 y^2$. This critical point is a:

lenght - a width - b Area= a*b 320=ab b=4/5a 320= 4 a 2 /5 400= a 2 a= 400 ​ a=20 b=16

Answered by mackiemesser | 2024-06-10

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Answered by repraiseds | 2024-06-12

The length of the room is 20 feet, and the width is 16 feet. The width is 5 4 ​ of the length, which leads us to these measurements. The area of the room confirms the calculations as it equals 320 square feet.
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Answered by mackiemesser | 2025-01-12