I need to find the length and the width of a rectangle that has an area of 9 in² and a given perimeter.

The perimeter = (2 lengths) + (2 widths) = 12
(1 length) + (1 width) = 6
Area = (length) x (width)
So you need two numbers that add to 6 and multiply to 9 .
How about 3 and 3 ?
Area = 3 x 3 = 9 Perimeter = 3 + 3 + 3 + 3 = 12
It works, and your rectangle is actually a square !

Answered by AL2006 | 2024-06-10

To find the dimensions of a rectangle given its area of 9 in² and perimeter of 12 in, you set up two equations based on the formulas for area and perimeter. Solving these equations shows that both the length and the width are 3 inches, meaning the shape is a square. Thus, the dimensions of the rectangle are length = 3 in and width = 3 in.
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Answered by AL2006 | 2024-12-23