A spinner is divided into 10 equal sections numbered from 0 to 10. You spin the spinner once. What is [tex]P(\text{divisible by 3})[/tex]?
Answer (2)
a ll : 0 , 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 , 10 → e l e v e n n u mb ers d i v i s ib l e b y 3 : 0 , 3 , 6 , 9 → f o u r n u mb ers ∣Ω∣ = 11 an d ∣ A ∣ = 4 ⇒ P ( A ) = 11 4
The probability of landing on a number divisible by 3 when spinning a spinner numbered from 0 to 10 is 11 4 . This is because there are 4 favorable outcomes (0, 3, 6, and 9) out of a total of 11 outcomes. Therefore, P ( A ) = 11 4 .
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