Austin & Kaitlyn Kojan invested $195,000 in a business venture. If Kaitlyn invested $2 \frac{1}{4}$ times as much as Austin invested, how much money did Kaitlyn invest?

Question

kate200468 · Answer

K ai tl y n = 2 4 1 ​ ⋅ A u s t in K ai tl y n + A u s t in = $195 , 000 2 4 1 ​ ⋅ A u s t in + A u s t in = $195 , 000 3 4 1 ​ ⋅ A u s t in = $195 , 000 4 13 ​ ⋅ A u s t in = $195 , 000 / ⋅ 13 4 ​ A u s t in = 13 ⋅ $15 , 000 ⋅ 13 4 ​ = $60 , 000 K ai tl y n = 2 4 1 ​ ⋅ A u s t in = 4 9 ​ ⋅ $60 , 000 = 9 ⋅ $15 , 000 = $135 , 000 A n s . \Kaitlyn d i d $135 , 000 in v es t .

kate200468 · Answer

Austin invested $60,000 and Kaitlyn invested $135,000. Kaitlyn's investment is 2.25 times Austin's investment. This solution was found by setting up equations based on their total investment and Kaitlyn's relation to Austin's investment. 
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Austin & Kaitlyn Kojan invested $195,000 in a business venture. If Kaitlyn invested \(2 \frac{1}{4}\) times as much as Austin invested, how much money did Kaitlyn invest?

Answer (2)

Austin & Kaitlyn Kojan invested $195,000 in a business venture. If Kaitlyn invested \(2 \frac{1}{4}\) times as much as Austin invested, how much money did Kaitlyn invest?

Answer (2)

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