The sum of two numbers is 44. The larger number is 20 more than the smaller number. What are the numbers?

Let the numebrs be x and y.
x + y = 44 x = y + 20
Substituting the value of x,
(y + 20) + y = 44
2y + 20 = 44 2y = 24 y = 12.
x = y + 20 x = 12+ 20
Thus, x = 32.
Thus, the two numbers are 32 and 12.

Answered by tadvisohil886 | 2024-06-10

The smaller number is 'x' . The larger number is (x+ 20)
Their sum is [ x + (x + 20 ]
2x + 20 = 44
Subtract 20 from each side:
2x = 24
Divide each side by 2 :
x = 12 and x + 20 = 32

Answered by AL2006 | 2024-06-10

The larger number is 32, and the smaller number is 12. These numbers satisfy both the condition of their sum being 44 and that the larger number is 20 more than the smaller number. We found these values by setting up and solving a system of equations.
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Answered by tadvisohil886 | 2024-09-30