A microscope is set so it makes an object appear [tex]$4 \times 10^2$[/tex] times larger than its actual size. A virus has a diameter of [tex]$2 \times 10^{-7}$[/tex] meter. How large will the diameter of the virus appear when it is viewed under the microscope?
Answer (2)
2 ⋅ 1 0 − 7 m e t er → t h e a c t u a l s i ze sc a l e = 4 ⋅ 1 0 2 t h e s i ze u n d er t h e mi crosco p e = 4 ⋅ 1 0 2 ⋅ 2 ⋅ 1 0 − 7 m e t er = 8 ⋅ 1 0 − 5 m e t er A n s . t h e s i ze u n d er t h e mi crosco p e i s 8 ⋅ 1 0 − 5 m e t er .
The diameter of the virus will appear as 8 × 1 0 − 5 meters when viewed under the microscope. This is calculated by multiplying the actual size of the virus 2 × 1 0 − 7 meters by the magnification factor 4 × 1 0 2 . Therefore, the size under magnification is 80 μ m .
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