The copper wire and bulb are connected in series with a 220 V electric supply. Why does only the electric bulb glow while the copper wire remains unchanged?

**Give a reason to support your answer.**

-- In a series circuit, the current ( I ) is the same at every point.
-- The power dissipated by any section of the circuit is I² x Resistance.
-- The wire has very low resistance, so I²R is very low dissipated power.
-- The filament in the bulb has most all of the resistance in the circuit, so it dissipates virtually all the power of the circuit, and certainly much more than the wires do.

Answered by AL2006 | 2024-06-10

In a series circuit, the copper wire has low resistance, resulting in little power dissipation, while the bulb has high resistance, allowing it to glow by converting electrical energy into light. Consequently, most of the voltage is utilized by the bulb, causing it to illuminate. The wire remains unchanged because it does not generate significant heat or light.
;

Answered by AL2006 | 2025-06-15