The positive integer \( x \) is a multiple of 9 and also a multiple of 12. What is the smallest possible value of \( x \)?

(A) 3
(B) 12
(C) 21
(D) 36
(E) 72

x is multiple of 9 as well as 12.
Thus, smallest value will be 36 ( 9 *4 = 36, 12 * 3 = 36)
3 and 12 are not the multiples of 9.
72 is a larger multiple than 36; thus, the correct answer is 36.

Answered by tadvisohil886 | 2024-06-10

If the positive integer x is a multiple of 9 and also a multiple of 12 then the smallest possible value of x is 36, option D is correct.
To find the smallest possible value of x that is both a multiple of 9 and a multiple of 12.
Find the least common multiple (LCM) of 9 and 12.
The prime factorization of 9 is 3 2 , and
the prime factorization of 12 is 2 2 × 3.
To find the LCM , we take the highest power of each prime factor:
L CM = 2 2 × 3 2
L CM = 36
Therefore, the smallest possible value of x is 36, which corresponds to option (D).
To learn more on Factorization click:
https://brainly.com/question/29763746
#SPJ6

Answered by pukhrajvt | 2024-06-18

The smallest positive integer x that is a multiple of both 9 and 12 is 36, which is option (D). To find this, we calculated the least common multiple (LCM) of 9 and 12 using their prime factorizations.
;

Answered by pukhrajvt | 2025-06-16