If \(\frac{3+y}{y} = 7\), then y = ?
Answer (3)
\frac{\big{3+y}}{\big{y}}=7\ \ \ \Rightarrow\ \ \ D:\ y \neq 0\\\\ \frac{\big{3+y}}{\big{y}}\cdot y=7\cdot y\\\\3+y=7y\\\\y-7y=-3\\\\-6y=-3\ /:(-6)\\\\y= \frac{3}{6} \\\\y= \frac{1}{2} \ \in\ D
y 3 + y = 7 3 + y = 7 y 1 y − 7 y = − 3 − 6 y = − 3 y = − 6 − 3 = 2 1 y = 2 1
The solution to the equation y 3 + y = 7 is y = 2 1 . This is found by multiplying both sides by y , rearranging the equation, and isolating y . Hence, y is correctly determined to be 2 1 .
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