Two identical freight cars roll without friction towards each other on a level track. One car rolls at 2 m/s, and the other at 1 m/s. After the cars collide, they couple and roll together with a speed of:

If they have identical weights the momentum is 2 m for one and -1 m for the other one. The total momentum is m, while the total mass is 2*m, giving a final speed of 0.5 m/s :|

Answered by Anonymous | 2024-06-10

The cars coupled and rolled together at a speed of 1.5 m/s.
What is law of conservation of linear momentum?
According to the** law of conservation of linear momentum**, the sum of the momentum before and after the collision must be equal.
m₁ u₁ + m₂u₂ = m₁ v₁ + m₂ v₂
where m₁ and m₂ is the mass of the collided objects, u₁ and u₂ are their initial speed while v₁ & v₂ is their final speed.
The** linear momentum** of an object can be defined as the product of the mass of the object times the velocity of that object.** Conservation of momentum **is a property held by an object where the total amount of momentum never changes.
Given the **initial velocity **of the car is u₁ = 2 m/s and the other car is u₂ = 1 m/s.
The masses of both cars is identical , m₁ = m₂ = m
From the law of conservation of momentum, find the speed of coupled cars (v),
m₁ u₁ + m₂ u₂ =m₁ v₁ + m₂v₂
m × 2 + m ×1 = m × v + m × v
2 + 1 = 2 v
2v = 3
v = 1.5 m/s
Therefore, the speed of the **coupled cars **is equal to 1.5 m/s.
Learn more about** the law of conservation of linear momentum**, here:
brainly.com/question/17140635
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Answered by sarbajitpanda | 2024-06-16

By applying the law of conservation of momentum, the initial momentum of the two identical freight cars before their collision is conserved after they couple together. The calculated speed of the coupled cars after the collision is 1.5 m/s. This result shows that even though one car was moving faster, the coupled system's speed reflects both initial speeds when combined.
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Answered by sarbajitpanda | 2024-09-19