The copper wire and bulb are connected in series with a 220 V electric supply. Why does only the electric bulb glow while the copper wire remains unchanged? Provide a reason to support your answer.

-- In a series circuit, the current ( I ) is the same at every point.
-- The power dissipated by any section of the circuit is I² x Resistance.
-- The wire has very low resistance, so I²R is very low dissipated power.
-- The filament in the bulb has most all of the resistance in the circuit, so it dissipates virtually all the power of the circuit, and certainly much more than the wires do.

Answered by AL2006 | 2024-06-10

In a series circuit, the bulb glows because it has a higher resistance compared to the copper wire, which has very low resistance. The power dissipated in the bulb due to its resistance causes it to emit light, while the wire dissipates very little power and remains unchanged. Therefore, only the bulb lights up in this circuit.
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Answered by AL2006 | 2025-04-13