what's the area of this circle?
Answer (2)
a= \pi r^{2} \ a= \pi 6^{2} \ a= \pi 36 \ a=113.0973355[/tex]
r = 6 in A = π r 2 A = π ⋅ 6 2 A = 36 π i n 2
a= \pi r^{2} \ a= \pi 6^{2} \ a= \pi 36 \ a=113.0973355[/tex]
r = 6 in A = π r 2 A = π ⋅ 6 2 A = 36 π i n 2
