Simplify the expression: [tex]z^2 - z(z + 3) + 3z[/tex]

The part in the middle is -z(z + 3) becomes -z² - 3z .
Those two negative things cancel the two positive things in the expression . . . well, here, let me show you :
z² - z(z + 3) + 3z =* z² [ - z² - 3z ] + 3z* . . . and that all adds up to exactly zero .

Answered by AL2006 | 2024-06-10

This isn't English :) but :
z(z) becomes z^2 and -z (3) becomes -3z when you distribute. z^2 -z^2 - 3z + 3z = z^2 - z^2 = 0

Answered by nicky442 | 2024-06-10

The expression z 2 − z ( z + 3 ) + 3 z simplifies to 0. This is achieved by distributing the middle term and combining like terms. Ultimately, all components cancel each other out.
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Answered by AL2006 | 2024-12-24