n + 3 ( n + 1 ) = 79 + 3 n + 3 = 79 4 n = 79 − 3 4 n = 76 / : 4 = 19 + 1 = 20 A n s w er : B . 19 an d 20.
The two consecutive integers are 19 and 20 based on the equation derived from the condition given. The calculations show that adding the smaller integer 19 to triple the larger integer 20 equals 79. Thus, the answer is B. 19, 20.
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