When \( x = 3 \) and \( y = 5 \), by how much does the value of \( 3x^2 - 2y \) exceed the value of \( 2x^2 - 3y \)?
F. 4
G. 14
H. 16
J. 20
K. 50
Answer (2)
3 ⋅ 3 2 − 2 ⋅ 5 − ( 2 ⋅ 3 2 − 3 ⋅ 5 ) = 27 − 10 − ( 18 − 15 ) = 17 − 3 = 14
The value of 3 x 2 − 2 y exceeds the value of 2 x 2 − 3 y by 14 . Therefore, the answer is G. 14.
;
