IdeasCuriosas - Every Question Deserves an Answer Logo

In Mathematics / Middle School | 2014-06-11

A circle has a circumference of [tex]$16\pi$[/tex] feet. What is the radius of the circle, in feet?

A. [tex]\sqrt{8}[/tex]
B. 4
C. 8
D. 16
E. 32

Asked by Gubbins430

Answer (3)

C = 16 π f t . C = 2 π r ( r − r a d i u s ) 2 π r = 16 π / : 2 π r = 8 ( f t . ) A n s w er : C

Answered by Anonymous | 2024-06-24

The radius of a circle can be found using the formula:
circumference = 2πr
Given that the circumference is 16π feet
Substitute the value into the formula: 16π = 2πr
Solve for r by dividing both sides by 2π, giving r = 8 feet

Answered by LivUllmann | 2024-06-24

The radius of the circle, given its circumference of 16π feet, is 8 feet. This is found using the formula for circumference: C = 2πr. Hence, the answer is option C.
;

Answered by Anonymous | 2024-09-30

Related Questions in Mathematics

[Answered] Select the correct answer. Which equation is equivalent to the given equation? [tex]$x^2-6 x=8$[/tex] A. [tex]$(x-6)^2=44$[/tex] B. [tex]$(x-3)^2=17$[/tex] C. [tex]$(x-6)^2=20$[/tex] D. [tex]$(x-3)^2=14$[/tex]

[Answered] Which phrase best describes the translation from the graph [tex]y=6 x^2[/tex] to the graph of [tex]y=6(x+1)^2[/tex]? A. 6 units left B. 6 units right C. 1 unit left D. 1 unit right

[Answered] What expression is equivalent to [tex]$\left(5 z^2+3 z+2\right)^2$[/tex] ? A. [tex]$5 z^4+3 z^2+4$[/tex] B. [tex]$5 z^4+9 z^2+4$[/tex] C. [tex]$25 z^4+30 z^3+19 z^2+12 z+4$[/tex] D. [tex]$25 z^4+30 z^3+29 z^2+12 z+4$[/tex]

[Answered] The graph of [tex]y=\frac{5}{4} x+1[/tex] is shown below. The coordinate ([tex]0, y[/tex]) is a solution of the equation. Given the [tex]x[/tex]-value of 0, what is the value of the [tex]y[/tex]-coordinate for the coordinate ([tex]0, y[/tex])? [tex]y=[/tex] [blank]

[Answered] If [tex]f(-2)=0[/tex], what are all the factors of the function [tex]f(x)=x^3-2 x^2-68 x-120[/tex]? Use the Remainder Theorem. A. [tex](x+2)(x+60)[/tex] B. [tex](x-2)(x-60)[/tex] C. [tex](x-10)(x+2)(x+6)[/tex] D. [tex](x+10)(x-2)(x-6)[/tex]