Calculate the conductance of a conduit with a cross-sectional area of 3.0 cm\(^2\) and a length of 9.0 cm, given that its conductivity is 0.80 ohm\(^{-1}\)cm\(^{-1}\).
Answer (3)
for resistance we have R=ρ l/a thus for conductance we have K=σ a/l conductance,K=1/R conductivity,σ =1/ρ
σ = .80 Ω-1 cm-1 l =9 cm a = 3 cm² K=.80 ×3/9 =0.26 Ω-1
Specific conductance or conductivity is the conductance for unit volume of a solution.
κ = C × a l
where,
κ =Specific conductance or Conductivity= 0.80 o h m − 1 c m − 1
C = Conductance = ?
l = length= 9.0 cm
a = area = 3.0 c m 2
a re a l e n g t h = cell constant = 3.0 c m 2 9.0 c m = 3 c m − 1
0.80 o h m − 1 c m − 1 = C × 3 c m − 1
C = 0.266 o h m − 1
The conductance of the conduit is calculated using the formula C = κ × l A . Substituting the given values, the conductance is approximately 0.27 ohm − 1 .
;
