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In Physics / High School | 2014-06-12

Determine the potential difference between two charged parallel plates that are 0.20 cm apart and have an electric field strength of 6.0 V/cm.

Asked by historygeek96

Answer (3)

V = E d = 0.20 × 6 = 1.20

Answered by miaumiau | 2024-06-10

V=E d d=.20 cm E=6 V/cm V=.20×6 =1.2 V

Answered by kuku | 2024-06-10

The potential difference between the two charged parallel plates is 1.20 volts, calculated using the formula V = E × d. By substituting the given values of electric field strength and distance, we arrive at this result. Therefore, V = 6.0 V/cm × 0.20 cm = 1.20 V.
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Answered by miaumiau | 2024-10-01

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