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In Physics / High School | 2014-06-13

Compute the resistance in ohms of a copper block 5.0 cm long and 0.10 cm\(^2\) in cross-sectional area. Given that \(\rho = 1.77 \times 10^{-6}\) ohm-cm.

Asked by historygeek96

Answer (2)

R=ρ l/a l=5 cm a=0.10 cm² ρ=1.77×10∧-6 Ωcm R=(1.77×10∧-6) ×5/0.10 =8.85 ×10∧-5 Ω
resistance is directly proportional to length and inversly proportional to area of cross section is given by above equation

Answered by kuku | 2024-06-10

The resistance of the copper block is calculated to be 8.85 × 1 0 − 5 ohms using the formula R = A ρ L ​ . The values for resistivity, length, and area were plugged into the formula to compute the result. This shows how resistance depends on both the dimensions and the material properties.
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Answered by kuku | 2024-12-24