A body of mass 2 kg moving in the positive X-direction with a speed of 4 m/s collides head-on with another body of mass 3 kg moving in the negative X-direction with a speed of 1 m/s. During the collision, a loud sound is heard, and they both start moving together. The sound energy cannot be greater than:
A) 12 J
B) 14 J
C) 15 J
D) 17.5 J
Answer (2)
m 1 = 2 m 2 = 3 v 1 = 4 v 2 = 1 v =speed after collision (to be determined) .
The momentul of the system preserves:
m 1 v 1 − m 2 v 2 = ( m 1 + m 2 ) v ⇒ v = m 1 + m 2 m 1 v 1 − m 2 v 2 .
Ok, we found the speed after the collision. Now, because the impact is plastic, it produces heat, sound energy and who knows what other forms of energy. We denote all this wasted energy with E .
Now, we write the energy conservation law:
2 m 1 v 1 2 + 2 m 2 v 2 2 = 2 ( m 1 + m 2 ) v 2 + E
From the above equation, you find E , and then conclude that the sound energy can certainly not be greater than this.
The maximum sound energy released cannot be greater than 15 J, after calculating the initial and final kinetic energies during the collision. The correct answer is option C) 15 J.
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