A turntable is designed to acquire an angular velocity of 32.4 rev/s in 0.5 seconds, starting from rest.
Find the average angular acceleration of the turntable during the 0.5-second period.
Answer in units of rad/s².
Answer (2)
Well, the acceleration is the difference of speeds divided by the time period. 0.5 32.4 = 64.8 re v / s 2 .
One rev/s is 2 π r a d / s 2 , so our final result is 64.8 ∗ 2 π = 407.15 r a d / s 2 .
not sure lol ;
