You're conducting a physics experiment on another planet. You drop a rock from a height of 1 m, and it hits the ground 0.4 seconds later. What is the acceleration due to gravity on this planet?

First, we must assume that the planet has no atmosphere, so there's no air resistance, and the behavior of the rock is the result of gravity and nothing else.
The formula for the distance covered by anything that accelerates from rest is
D = (1/2) (acceleration) (time)²
In this problem, we're given the distance and the time, and we want to find the acceleration.
1 = (1/2 acceleration) x (0.4)²
0.4² = 0.16
1 = (1/2 times 0.16) (acceleration)
1 = 0.08 acceleration
Acceleration = 1/0.08 = 12.5 meters per second²
That's about 27% greater than Earth's gravity.

Answered by AL2006 | 2024-06-24

12.5 ;

Answered by mohammedel04 | 2024-06-24

The acceleration due to gravity on the planet is approximately 12.5 m/s². This was calculated using the formula for motion under uniform acceleration, considering the height and time of the fall. This value is higher than Earth's gravitational acceleration.
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Answered by AL2006 | 2024-10-10