Solve the following system of equations:

1. \(2x - 3y = 14\)
2. \(2x - y = -10\)

2x-3y=14\ / \cdot(-1)\\2x-y=-10\\\\-2x+3y=-14\\2x-y=-10\\--------\\3y-y=-14-10\\2y=-24\ /:2\\y=-12\\\\2x-y=-10\\ \Rightarrow\ \ \ 2x-(-12)=-10\ \ \ \Rightarrow\ \ \ 2x+12=-10\ \ \ \Rightarrow\ \ \ 2x=-22\ /:2\\\Rightarrow\ \ \ x=-11\\\\ \left \{{\big {x=-11} \atop \big {y=-12}} \right.

Answered by kate200468 | 2024-06-10

Hello there !
2 x − 3 y = 14 2 x − y = − 10 2 x − 3 y = 14 2 x = y − 10 y − 10 − 3 y = 14 − 10 − 14 = − y + 3 y − 24 = 2 y − 12 = y ​ 2 x − y = − 10 2 x − ( − 12 ) = − 10 2 x = − 10 − 12 2 x = − 22 = − 11 ​

Answered by Anonymous | 2024-06-10

The solution to the system of equations is x = − 11 and y = − 12 . This was achieved by using the elimination method and substituting values. The final set of values provides an accurate resolution to the system.
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Answered by kate200468 | 2025-02-19