Make the reaction: C H 4 + 2 O 2 = C O 2 + 2 H 2 O For 2 32=64 grams of oxygen, you can burn 2 16=32 grams of methane (that is, half). So, our answer is .5g. Other intermediate calculations are mollecular masses: μ C H 4 = A C + 4 A H = 12 + 4 = 16 m u O 2 = 2 A O = 2 ∗ 16 = 32
0.28 g of C H 4 ;
The maximum mass of methane (CH₄) that can be burned with 1.0 g of oxygen (O₂) is 0.25 grams. This is calculated using the stoichiometry of the combustion reaction, taking into account the molar masses of the reactants. Specifically, 1 mole of CH₄ requires 2 moles of O₂ for complete combustion.
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