A large passenger aircraft accelerates down the runway for a distance of 3300 m before leaving the ground. It then climbs at a steady 6.3-degree angle. After the plane has traveled 3200 m along this new trajectory, how high is it?
Answer (2)
s in 6. 3 o = 3200 h s in 6. 3 o ≈ 0.1097 3200 h = 0.1097 / ⋅ 3200 h ≈ 351 ( m ) A n s w er : 351 m
Using trigonometry, we determined that after climbing 3200 m at a 6.3-degree angle, the aircraft reaches a height of approximately 351 m. This calculation utilizes the sine function to relate the height to the climb distance and angle. Therefore, the final height is about 351 m.
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