The accepted value for the percent by mass of water in a hydrate is 36.0%. In a laboratory activity, a student determined the percent by mass of water in the hydrate to be 37.8%. What is the percent error for the student's measured value?

(1) 5.0%
(2) 4.8%
(3) 1.8%
(4) 0.05%

5% ;

Answered by nak767954 | 2024-06-14

The original or accepted value for the percent by mass of water in a hydrate = 36% Percen by mass of water in the hydrate determined by the student in the laboratory = 37.8% So the difference between the actual and the percent by mass in water determined by student = (37.8 - 36.0)% = 1.8% So the percentage of error made by the student = (1.8/36) * 100 percent = (18/360) * 100 percent = ( 1/20) * 100 percent = 5 percent So the student makes an error of 5%. Option "1" is the correct option.

Answered by taskmasters | 2024-06-24

The percent error of the student's measured value of water in the hydrate is calculated to be 5.0%. This is done by first finding the absolute error and then the percent error based on the accepted value. Therefore, the correct answer is option (1) 5.0%.
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Answered by taskmasters | 2024-09-16