Which chemical equation best describes the reaction of potassium metal with fluorine gas to form solid potassium fluoride?
A. K(s) + F2(g) → KF2(s)
B. K(s) + F(g) → KF(s)
C. K2(g) + F2(g) → 2 KF(s)
D. 2 K(s) + F2(g) → 2 KF(s)
Answer (2)
A. K(s) + F2(g) → KF2(s)
B. K(s) + F(g) → KF(s)
C. K2(g) + F2(g) → 2 KF(s)
D. 2 K(s) + F2(g) → 2 KF(s) it exists as a pale yellow d iatomic gas at standard conditions!!
The correct chemical equation for the reaction of potassium with fluorine gas to form potassium fluoride is option D: 2 K(s) + F2(g) → 2 KF(s). This equation reflects the proper stoichiometric ratio and phases of the reactants and products. It adheres to the law of conservation of matter, ensuring that atoms are balanced on both sides.
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