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In Physics / High School | 2014-07-07

A wire is 2 m long and has a diameter of 0.1 mm and a resistance of 20 ohms. Calculate the resistivity of its material.

Asked by CarmellaStoltzfus

Answer (2)

R= A p L ​
R-resistance p-resistivity [Ohm m] A-cross sectional area L-length R=20 Ohm l=2m A= π r 2 = π ( 0 , 01 ) 2 = 0 , 000314 c m 2 =0,314 1 0 − 7 m² p= L R ∗ A ​ p= 2 20 ∗ 0 , 314 ∗ 1 0 − 7 ​ =0,000000314 Ohm*m

Answered by luana | 2024-06-10

The resistivity of the material in the wire is approximately 7.85 x 10^-8 ohm-meters. This was calculated using the formula for resistance, taking into account the wire's length and cross-sectional area. The calculations show that the resistivity value is typical for conductive materials.
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Answered by luana | 2024-10-01

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