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In Physics / High School | 2014-07-07

A current of 4 A flows in a wire with a resistance of 60 ohms. Calculate the electrical energy consumed in 2 minutes.

Asked by KarimaSanfiorenzo594

Answer (2)

Power dissipated = energy/second= (current)² x (resistance)
Power dissipated = energy / second = (4)² x (60) = 960 joules per second= 960 watts
Energy = (power) x (time) = (960 watts) x (2 minutes) x (60 sec/minute)
= 115,200 joules

Answered by AL2006 | 2024-06-10

The electrical energy consumed by the wire over 2 minutes is calculated by first determining the power dissipated using the formula P = I 2 R . For a current of 4 A and a resistance of 60 Ω, the power is 960 W. The energy consumed in 2 minutes is then calculated as E = P × t , resulting in a total of 115,200 joules.
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Answered by AL2006 | 2024-12-24

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