If a grocery cart with a mass of 16.5 kg accelerates at [tex]+2.31 \, \text{m/s}^2[/tex] against a frictional force of [tex]-15.0 \, \text{N}[/tex], what is the applied force?

Call the applied force 'A'. (Clever ?)
The forces on the cart are 'A' forward and 15 N backward.
The net force on the art is (A-15) forward.
F = m a
Net forward force = (mass of the cart) x (its forward acceleration)
(A - 15) = (16.5) x (2.31)
A - 15 = 38.115
Add 15 to each side:
A = 53.115 newtons

Answered by AL2006 | 2024-06-10

2th Law of Newton:
R = m . a R = F − F a ​ ​ = m . a F − 15 = 16.5 ∗ 2.31 F = 38.115 + 15 F = 53.115 N ​

Answered by Ryan2 | 2024-06-10

The applied force on the grocery cart is approximately 53.115 N. This is calculated using Newton's second law by considering the mass of the cart, its acceleration, and the frictional force acting against its motion. By setting up the equation for net force and solving for the applied force, we arrive at this value.
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Answered by AL2006 | 2024-12-24