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In Physics / High School | 2014-07-11

A 76.5 kg cross-country skier skiing on unwaxed skis along dry snow at a constant speed of 4.00 m/s experiences a force of friction of -60.0 N. What is the coefficient of friction between unwaxed skis and dry snow?

A. 0.08
B. 0.78
C. 1.28
D. 12.5

Asked by lolonik99

Answer (2)

The force of friction = (weight) x (coefficient of friction)
Skier's weight = (mass) x (gravity) = (76.5) x (9.8) = 749.7 N
Force of friction = (749.7) x (coefficient of friction) = 60.0 N
Coefficient of friction = 60 / 749.7 = 0.08 (rounded)
Choice-'A' is the closest choice offered.

Answered by AL2006 | 2024-06-10

The coefficient of friction between the unwaxed skis and dry snow is approximately 0.08. This is calculated using the skier's weight and the known force of friction. Therefore, the correct option is (A) 0.08.
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Answered by AL2006 | 2024-10-02

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