2 1 a t 2 = d ∣ m u lt i pl y b o t h s i d es b y 2 a t 2 = 2 d ∣ d i v i d e b o t h s i d es b y a t 2 = a 2 d ∣ s q u a re roo t b o t h s i d es t = a 2 d
d = 2 1 a t 2 2 d = a t 2 t 2 = a 2 d t = a 2 d
To solve for t in the equation d = 2 1 a t 2 , we rearrange it to t = a 2 d . This allows us to calculate time given distance and acceleration. For example, covering 100 meters with an acceleration of 10 m/s² results in approximately 4.47 seconds.
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