substitute your point (3,-2) on both equations: A(3)+b(-2)=18 <--equation 1 a(3)-b(-2)=6 <--equation 2 add both equations, you'll get 6A=24 A=4
substitute the value of A in any equtions equation 1: (4)(3)-2b=18 simplify and solve for b, you'll get b=-3
thus, A=4 & B=-3
The values of A and B are A = 4 and B = -3. These were determined by substituting the intersection point into both equations and solving the resulting system of equations. This systematic approach allows us to find the unknown coefficients accurately.
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