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In Physics / High School | 2014-07-21

A man travels 10 km to the east and then 20 km to the north.

Find the distance moved and the displacement.

Asked by Anonymous

Answer (2)

x 2 = 1 0 2 + 2 0 2 x 2 = 100 + 400 x 2 = 500 x = 500 ​ = 10 5 ​ ≈ 22.36 km

Answered by konrad509 | 2024-06-10

The man moved a total distance of 30 km. His displacement, which is the straight-line distance from his starting point to his ending point, is approximately 22.36 km at an angle of 63.43° from east. This helps illustrate the difference between the total path traveled and the shortest distance to the final location.
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Answered by Anonymous | 2025-06-12

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