Solve for x.

\[ 4x^2 + 16x = 0 \]

4 x 2 + 16 x = 0
4 4 x 2 + 16 x ​ = 4 0 ​
x 2 + 4 x = 0
x ( x + 4 ) = 0
x = 0
x + 4 = 0
x + 4 − 4 = 0 − 4
x = − 4
x = − 4 , 0

Answered by iloveonedirection | 2024-06-10

Divide each side of the equation by 4 :
x² + 4x = 0
Factor the left side:
x (x + 4) = 0
This equation is true if x=0 or if x=-4 , so those are the two solutions.

Answered by AL2006 | 2024-06-10

To solve 4 x 2 + 16 x = 0 , we factor it to get 4 x ( x + 4 ) = 0 . This results in the solutions x = 0 and x = − 4 . Both solutions can be verified by plugging back into the original equation.
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Answered by iloveonedirection | 2025-02-21