An experiment consists of rolling two fair number cubes. What is the probability that the sum of the two numbers will be 4? Express your answer as a fraction in simplest form.
(a) \(\frac{11}{18}\)
(b) \(\frac{1}{12}\)
(c) \(\frac{12}{1}\)
(d) \(\frac{11}{12}\)
Answer (2)
The probability of rolling a sum of 4 with two fair number cubes is 1/12.
We must determine the number of ways we can obtain this sum and divide it by the total number of possible outcomes.
When working with two dice, each die has 6 faces, so there are a total of
6 x 6 = 36 possible outcomes
To achieve a sum of 4, we have the following possibilities:
(1,3), (2,2), and (3,1)
This gives us 3 favorable outcomes.
Hence,
probability = 3/36
probability = 1/12
The probability of rolling a sum of 4 with two fair number cubes is 12 1 . This is found by identifying the 3 favorable outcomes (1,3), (2,2), and (3,1) out of 36 total outcomes. Therefore, the correct answer is (b) 12 1 .
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