One circular table has a diameter of 9 ft, and another circular table has a diameter of 14 ft. How much greater is the area of the larger table? Round to the nearest whole number.
Answer (3)
A re a o f a C i rc l e : A = π r 2 d iam e t er : d 1 = 9 f t r a d i u s : r 1 = 2 d 1 = 2 9 = 4.5 f t d 2 = 14 f t r a d i u s : r 2 = 2 d 1 = 2 14 = 7 f t A 1 = ( 4.5 ) 2 π = 20 , 25 c d o t 3.14 = 63.585 f t 2 A 2 = 7 2 π = 49 ⋅ 3.14 = 153.86 f t 2 A 2 − A 1 = 153.86 − 63.585 = 90.275 ≈ 90 f t 2
Area of circle= πr² r-radius
A1-area of table with diameter 9ft A2-area of circle with diameter 14ft d=2r
A1=π*(4,5)²=20,25π A2=π*7²=49π
A2-A1=49π-20,25π=28,75π=90,275≈90ft²
The area of the larger table (14 ft diameter) is approximately 90 ft² greater than the area of the smaller table (9 ft diameter).
;
