56 + 4 = 60 60 × 3 = 180 180 : 2 = 90 C H EC K : 3 2 × 90 − 4 = 2 × 30 − 4 = 60 − 4 = 56
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128 − 38 = 90 90 × 9 = 810 810 : 5 = 162 C H EC K : 38 + 9 5 × 162 = 38 + 5 × 18 = 38 + 90 = 128
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14.6 − 2.3 = 12.3 12.3 × 5 = 61.5 61.5 : 3 = 20.5 C H EC K : 5 3 × 20.5 + 2.3 = 3 × 4.1 + 2.3 = 12.3 + 2.3 = 14.6
Let the number be x There are actually 3 different statements -
two-thirds of a number decreased by 5 is 56 2 x/3 - 4 =56 2 x/3=60 x=90
38 added to 5/9 of number gives 128 i.e 5 x/9 + 38 = 128 5 x/9 = 90 x = 162
sum of 2.3 and 3/5 of number gives 14.6 i.e 2.3 + 3 x/5 = 14.6 3 x/5 = 12.3 x = 4.1*5 x = 20.5
The solutions to the three problems are as follows: The first number is 90, the second number is 162, and the third number is 20.5. Each solution was calculated step-by-step to isolate the variable representing the unknown number.
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