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In Mathematics / Middle School | 2014-07-29

1. If two-thirds of a number is decreased by 4, the result is 56. Find the number.

2. If 38 is added to \(\frac{5}{9}\) of a number, the result is 128. Find the number.

3. The sum of \(\frac{3}{5}\) of a number and 2.3 is 14.6. Find the number.

Asked by Anonymous

Answer (3)

56 + 4 = 60 60 × 3 = 180 180 : 2 = 90 ​ C H EC K : 3 2 ​ × 90 − 4 = 2 × 30 − 4 = 60 − 4 = 56
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128 − 38 = 90 90 × 9 = 810 810 : 5 = 162 ​ C H EC K : 38 + 9 5 ​ × 162 = 38 + 5 × 18 = 38 + 90 = 128
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14.6 − 2.3 = 12.3 12.3 × 5 = 61.5 61.5 : 3 = 20.5 ​ C H EC K : 5 3 ​ × 20.5 + 2.3 = 3 × 4.1 + 2.3 = 12.3 + 2.3 = 14.6

Answered by Anonymous | 2024-06-10

Let the number be x There are actually 3 different statements -

two-thirds of a number decreased by 5 is 56 2 x/3 - 4 =56 2 x/3=60 x=90

38 added to 5/9 of number gives 128 i.e 5 x/9 + 38 = 128 5 x/9 = 90 x = 162

sum of 2.3 and 3/5 of number gives 14.6 i.e 2.3 + 3 x/5 = 14.6 3 x/5 = 12.3 x = 4.1*5 x = 20.5

Answered by Pulkit | 2024-06-10

The solutions to the three problems are as follows: The first number is 90, the second number is 162, and the third number is 20.5. Each solution was calculated step-by-step to isolate the variable representing the unknown number.
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Answered by Anonymous | 2024-12-24