Well, the configuration is 1 s 2 2 s 2 2 p 5 . To show the electrons, we have 1s as [ ], 2s as [ ], 2p as [ ][ ][*-], where * is an electron and - is a vacant slot. We have 5 occupied orbitals (4 fully occupied, one partially occupied)
A fluorine atom in its ground state has a total of 5 occupied orbitals. This includes 1 orbital from the 1s subshell, 1 from the 2s subshell, and 3 from the 2p subshell. The electron configuration can be noted as 1s² 2s² 2p⁵.
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