F or m u l a f or p er i o d : T = 2 π g L g − g r a v i t y = 9 , 8 s 2 m , L − p e n d u l u m l e n g t h 2 π T = g L ∣ s q u a re 2 π T 2 = g L 2 π T 2 ∗ g = L L = 2 ∗ 3 , 14 2 2 ∗ 9 , 8 = 6 , 28 39 , 2 = 6 , 24 m T = 2 π g L 2 π T = g L ∣ s q u a re 2 π T 2 = g L 2 π T 2 ∗ g = L L = 2 ∗ 3 , 14 2 2 ∗ 9 , 8 = 6 , 28 39 , 2 = 6 , 24 m
The length of a pendulum with a period of 2.0 seconds is approximately 0.991 meters (or 99.1 cm). This is calculated using the formula for the period of a pendulum. By rearranging the formula and solving for length, we arrive at the final answer.
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