AB = 4 x - 9 BC = 3 x + 5 AC = 7
B is in between A and C. So AB + BC = AC
4x - 9 + 3 x + 5 = 7 7 x - 4 = 7 take -4 from LHS to the R H S (right hand side) it becomes +4 7 x = 7 + 4 = 11 x = 11/7 = 1.571
By using the relationship between the lengths of segments where B lies between A and C, we derived that x = 7 11 , which is approximately 1.57. This was done by setting up the equation A B + BC = A C and solving for x .
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