Write the prime factorization of 6. Use exponents when appropriate and order the factors from least to greatest (for example, \(2^2 \cdot 3^1 \cdot 5^1\)).
Answer (3)
the prime factorization of 6, ordered from least to greatest, is 2 1 ∗ 3 1 .
To find the prime factorization of 6:
Divide 6 by the smallest prime number, 2:
6 ÷ 2 = 3
Since 3 is a prime number, we cannot divide it further.
So, the prime factorization of 6 is:
6 = 2 × 3
We can write this in exponential form as:
6 = 2 1 ∗ 3 1
Therefore, the prime factorization of 6, ordered from least to greatest, is 2 1 ∗ 3 1 .
The prime factorization of 6 is finding the prime numbers that multiply together to make 6. Prime factorization does not involve exponents if the prime factors are not repeated. The number 6 can be factored into 2 and 3, which are both prime numbers.
To find the prime factorization of 6 , we first recognize that 6 is an even number, so it is divisible by 2. The factors of 6 are:
Divide 6 by 2, which gives us 3
Now we have 2 and 3, both of which are prime numbers
Therefore, the prime factorization of 6 is 2 × 3. Since there are no repeated factors, we do not use exponents. We write the prime factors in ascending order, so no further arrangement is needed.
The prime factorization of 6 is expressed as 2 1 × 3 1 . This is found by dividing 6 by its smallest prime factor and continuing until all factors are prime. The final result is that 6 is made up of the prime numbers 2 and 3, each raised to the power of 1.
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