Find the original two-digit number given the following conditions:

1. The digit in the tens place is three times the digit in the units place.
2. If the digits are reversed, the new number is 36 less than the original number.

Use one variable to solve the problem.

We could do it with algebra. But we can also do it the long way, which is shorter than the algebraic way.
The digit in the tens place is 3 times the digit in the units place. So the number MUST be 31, or 62, or 93 . It can't be anything else.
Now here they are again, with the reverse of each one:
31 . . . 13 The new number is 18 less. 62 . . . 26 The new number is 36 less .
93 . . . 39 The new number is 54 less.
Obviously, the original number is 62.

Answered by AL2006 | 2024-06-10

The original two-digit number is 62, where the tens digit is three times the units digit. Reversing the digits results in 26, which is 36 less than 62. The conditions are satisfied, confirming the solution.
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Answered by AL2006 | 2024-12-18