they could all be 8.
2014 is not a multiple of 5, so there is no cycle of 5 numbers which repeats
I believe the only way that ANY five successive numbers could have the same sum would be for all of the numbers to be the same. All of them must be 8s .
The 2014 numbers on the circle must be part of a repeating sequence of 5 numbers that add up to 40. For example, one possible solution is having each of the 5 numbers equal to 8. Therefore, any combination of numbers that averages to meet the same criteria will work as valid configurations.
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