Solve for \( n \).

\[ 2(n-3) = 4n + 1 \]

2(n-3)=4n+1
2n-6=4n+1
-6-1=4n-2n
2n=-7
n=(-7)/2

Answered by Anonymous | 2024-06-10

2 ( n − 3 ) = 4 n + 1 2 n − 6 = 4 n + 1 2 n = − 7 n = − 2 7 ​

Answered by konrad509 | 2024-06-10

The solution to the equation 2 ( n − 3 ) = 4 n + 1 is n = − 2 7 ​ . This was found by distributing, rearranging the equation, and then isolating n .
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Answered by Anonymous | 2024-12-26