The ratio of adults to students is 1:10. Last year, there were 477 more students than adults at prom. If the school is expecting the same attendance this year, how many adults have to attend?
Answer (3)
x -number of adults x+477 -number of students
We want to make students 10 times more numerous then adults. When creating equation we need to multiply number of adults by 10, to make both sides even (thats why there is 10x, so ten times the number of students) x+477=10x /-x from both sides 477=9x 53=x
Let's check is 53 ten times less then 53+477(530). It is. So 53 adults have to attend the prom.
To maintain a ratio of 1:10 adults to students, with 477 more students than adults, at least 53 adults need to attend this year's school prom.
To find out how many adults need to attend the school prom given the ratio of adults to students is 1:10 and that last year there were 477 more students than adults, we can set up an algebraic equation. Let's denote the number of adults as 'A' and the number of students as 'S'. According to the given ratio, S = 10A. We also know there were 477 more students than adults last year, so
S = A + 477.
When we equate the two expressions for S, we get:
10A = A + 477.
Subtracting A from both sides, we get
9A = 477.
Dividing both sides by 9, we find that A, the number of adults, equals 53.
Therefore, at least 53 adults have to attend this year's school prom to maintain the same ratio.
The number of adults that attended last year’s prom is 53. Since the school is expecting the same attendance this year, 53 adults need to attend the prom again. This follows from the established ratio and the additional difference given in the problem.
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