A car moving at 4.5 m/s accelerates at [tex]2.5 \, \text{m/s}^2[/tex]. After 7 seconds, how fast will it be moving?
Answer (3)
The formula is V = final velocity = initial velocity U + ( acceleration a * time duration t ) V = U + a t = 4.5 m/s + 2.5 m/sec² * 7 sec = 4.5 + 17.5 = 22 m /sec
Acceleration means, every second the velocity or speed increases by that amount. Here it is 2.5. After one second velocity become 2.5 m/s more. after 2 seconds it is 5 m/s more. after 3 seconds, speed is 7.5 m/s more than at start. Like this after 7 seconds, the speed is 7 * 2.5 higher than at the beginning. so computer the total.
The car, initially moving at 4.5 m/s and accelerating at 2.5 m/s², will reach a final velocity of 22 m/s after 7 seconds.
The question involves calculating the final velocity of a car accelerating over a certain period. This can be solved using the basic kinematics equation Vf = Vi + a*t, where Vf is the final velocity, Vi is the initial velocity, a is the acceleration, and t is the time. Given that the car is moving at an initial velocity (Vi) of 4.5 m/s and accelerates at 2.5 m/s² for 7 seconds (t), the final velocity (Vf) can be calculated as follows:
Vf = Vi + a*t Vf = 4.5 m/s + (2.5 m/s² * 7 s) Vf = 4.5 m/s + 17.5 m/s Vf = 22 m/s
So, after 7 seconds, the car will be moving at 22 m/s.
The final velocity of the car after accelerating for 7 seconds at 2.5 m/s² from an initial speed of 4.5 m/s is 22 m/s. This is calculated using the formula V = U + a t. Thus, the car accelerates to 22 m/s after the specified time.
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